3c^2(c^2+3)=112+4c^2

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Solution for 3c^2(c^2+3)=112+4c^2 equation: 



3c^2(c^2+3)=112+4c^2

We move all terms to the left:

3c^2(c^2+3)-(112+4c^2)=0

We get rid of parentheses

3c^2(c^2+3)-4c^2-112=0

We add all the numbers together, and all the variables

-4c^2+3c^2(c^2+3)-112=0

We move all terms containing c to the left, all other terms to the right

-4c^2+3c^2(c^2+3)=112

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